久久久久久精品无码人妻_青春草无码精品视频在线观_无码精品国产VA在线观看_国产色无码专区在线观看

代寫COMP9021、代做Python程序語言

時間:2024-03-27  來源:  作者: 我要糾錯



COMP9021 Principles of Programming
Term 1, 2024
Assignment 1
Worth 13marks and due Week 7 Monday @ 10am
1. General Matters
1.1 Aim
The purpose of this assignment is to:
• develop your problem-solving skills.
• design and implement the solution to a problem in the form of a medium sized Python program.
• practice the use of arithmetic computations, tests, repetitions, lists, and strings.
• use procedural programming.
1.2 Marking
This assignment is worth 13 marks distributed approximately as follows:
1.50 marks for "I don't get what you want, sorry mate!"
3.50 marks for "Hey, ask me something that's not impossible to do!"
2.25 marks for "Please convert ***"
2.50 marks for "Please convert *** using ***"
3.25 marks for "Please convert *** minimally"
 ----------------------------------------------------------------------
13.00 marks total
Your program will be tested against several inputs. For each test, the automarking script will let your
program run for 30 seconds. The outputs of your program should be exactly as indicated.
2
1.3 Due Date and Submission
Your program will be stored in a file named roman_arabic.py. The assignment can be submitted
more than once. The last version just before the due date and time will be marked (unless you submit late
in which case the last late version will be marked).
Assignment 1 is due Week 7 Monday 25 March 2024 @ 10:00am (Sydney time)
Note that late submission with 5% penalty per day is allowed up to 5 days from the due date, that is, any
late submission after Week 7 Saturday 30 March 2024 @ 10:00am will be discarded.
Make sure not to change the filename roman_arabic.py while submitting by clicking on [Mark]
button in Ed. It is your responsibility to check that your submission did go through properly using
Submissions link in Ed otherwise your mark will be zero for Assignment 1.
1.4 Reminder on Plagiarism Policy
You are permitted, indeed encouraged, to discuss ways to solve the assignment with other people. Such
discussions must be in terms of algorithms, not code. But you must implement the solution on your own.
Submissions are scanned for similarities that occur when students copy and modify other people’s work or
work very closely together on a single implementation. Severe penalties apply.
2. Description
You will design and implement a program that prompts the user for an input with:
How can I help you?
User input should be one of three possible kinds:
Please convert ***
Please convert *** using ***
Please convert *** minimally
If the user input is not of this form, with any occurrence of *** an arbitrary nonempty sequence
of non-space symbols, then the program should print out:
I don't get what you want, sorry mate!
and stop.
3
2.1 First Kind of Input
In case the user inputs Please convert ***, then *** should be either a strictly positive
integer (whose representation should not start with 0) that can be converted to a Roman number
(hence be at most equal to 3999), or a valid Roman number; otherwise, the program should
print out:
Hey, ask me something that's not impossible to do!
and stop.
If the input is as expected, then the program should perform the conversion, from Arabic to
Roman or from Roman to Arabic, and print out the result in the form:
Sure! It is ***
2.2 Second Kind of Input
In case the user inputs Please convert *** using ***, then the first *** should be
a strictly positive integer (whose representation should not start with 0) or a sequence of
(lowercase or uppercase) letters and the second *** should be a sequence of distinct
(lowercase or uppercase) letters.
Moreover:
• the second *** is intended to represent a sequence of so-called generalised
Roman symbols. The classical Roman symbols corresponding to the sequence
MDCLXVI, whose rightmost element is meant to represent 1, the second rightmost
element 5, the third rightmost element 10, etc.
• if it is not an integer, the first *** is intended to represent a so-called generalised
Roman number, that is, a sequence of generalised Roman symbols that can be decoded
using the provided sequence of generalised Roman symbols similarly to the way Roman
numbers are represented.
If that is not the case, or if it is not possible to convert the first *** from Arabic to generalised
Roman or from generalised Roman to Arabic, then the program should print out:
Hey, ask me something that's not impossible to do!
and stop.
4
If the input is as expected and the conversion can be performed, then the program should indeed perform
the conversion, from Arabic to generalised Roman or from generalised Roman to Arabic, and print out the
result in the form:
Sure! It is ***
2.3 Third Kind of Input
In case the user inputs Please convert *** minimally, then *** should be a sequence
of (lowercase or uppercase) letters. The program will try and view *** as a generalised Roman
number with respect to some sequence of generalised Roman symbols. If that is not possible,
then the program should print out:
Hey, ask me something that's not impossible to do!
and stop.
Otherwise, the program should find the smallest integer that could be converted from ***,
viewed as some generalised Roman number, to Arabic, and output a message of the form
Sure! It is *** using ***
5
3. Sample Outputs (or Test Cases)
Here are a few tests together with the expected outputs. The outputs of your program should be exactly
as shown:
$ python3 roman_arabic.py
How can I help you? Please do my assignment...
I don't get what you want, sorry mate!
$ python3 roman_arabic.py
How can I help you? please convert 35
I don't get what you want, sorry mate!
$ python3 roman_arabic.py
How can I help you? Please convert 035
Hey, ask me something that's not impossible to do!
$ python3 roman_arabic.py
How can I help you? Please convert 4000
Hey, ask me something that's not impossible to do!
$ python3 roman_arabic.py
How can I help you? Please convert IIII
Hey, ask me something that's not impossible to do!

6
$ python3 roman_arabic.py
How can I help you? Please convert IXI
Hey, ask me something that's not impossible to do!
$ python3 roman_arabic.py
How can I help you? Please convert 35
Sure! It is XXXV
$ python3 roman_arabic.py
How can I help you? Please convert 1982
Sure! It is MCMLXXXII
$ python3 roman_arabic.py
How can I help you? Please convert 3007
Sure! It is MMMVII
$ python3 roman_arabic.py
How can I help you? Please convert MCMLXXXII
Sure! It is 1982
$ python3 roman_arabic.py
How can I help you? Please convert MMMVII
Sure! It is 3007

7
$ python3 roman_arabic.py
How can I help you? Please convert 123 by using ABC
I don't get what you want, sorry mate!
$ python3 roman_arabic.py
How can I help you? Please convert 123 ussing ABC
I don't get what you want, sorry mate!
$ python3 roman_arabic.py
How can I help you? Please convert XXXVI using VI
Hey, ask me something that's not impossible to do!
$ python3 roman_arabic.py
How can I help you? Please convert XXXVI using IVX
Hey, ask me something that's not impossible to do!
$ python3 roman_arabic.py
How can I help you? Please convert XXXVI using XWVI
Hey, ask me something that's not impossible to do!
$ python3 roman_arabic.py
How can I help you? Please convert I using II
Hey, ask me something that's not impossible to do!

8
$ python3 roman_arabic.py
How can I help you? Please convert _ using _
Hey, ask me something that's not impossible to do!
$ python3 roman_arabic.py
How can I help you? Please convert XXXVI using XVI
Sure! It is 36
$ python3 roman_arabic.py
How can I help you? Please convert XXXVI using XABVI
Sure! It is 306
$ python3 roman_arabic.py
How can I help you? Please convert EeDEBBBaA using fFeEdDcCbBaA
Sure! It is 49036
$ python3 roman_arabic.py
How can I help you? Please convert 49036 using fFeEdDcCbBaA
Sure! It is EeDEBBBaA
$ python3 roman_arabic.py
How can I help you? Please convert 899999999999 using
AaBbCcDdEeFfGgHhIiJjKkLl
Sure! It is Aaaabacbdcedfegfhgihjikjlk

9
$ python3 roman_arabic.py
How can I help you? Please convert ABCDEFGHIJKLMNOPQRST using
AbBcCdDeEfFgGhHiIjJkKlLmMnNoOpPqQrRsStT
Sure! It is 11111111111111111111
$ python3 roman_arabic.py
How can I help you? Please convert 1900604 using LAQMPVXYZIRSGN
Sure! It is AMAZING
$ python3 roman_arabic.py
How can I help you? Please convert ABCD minimally using ABCDE
I don't get what you want, sorry mate!
$ python3 roman_arabic.py
How can I help you? Please convert ABCD minimaly
I don't get what you want, sorry mate!
$ python3 roman_arabic.py
How can I help you? Please convert 0I minimally
Hey, ask me something that's not impossible to do!
$ python3 roman_arabic.py
How can I help you? Please convert ABAA minimally
Hey, ask me something that's not impossible to do!

10
$ python3 roman_arabic.py
How can I help you? Please convert ABCDEFA minimally
Hey, ask me something that's not impossible to do!
$ python3 roman_arabic.py
How can I help you? Please convert MDCCLXXXVII minimally
Sure! It is 1787 using MDCLXVI
$ python3 roman_arabic.py
How can I help you? Please convert MDCCLXXXIX minimally
Sure! It is 1789 using MDCLX_I
$ python3 roman_arabic.py
How can I help you? Please convert MMMVII minimally
Sure! It is 37 using MVI
$ python3 roman_arabic.py
How can I help you? Please convert VI minimally
Sure! It is 4 using IV
$ python3 roman_arabic.py
How can I help you? Please convert ABCADDEFGF minimally
Sure! It is 49269 using BA_C_DEF_G
$ python3 roman_arabic.py
How can I help you? Please convert ABCCDED minimally
Sure! It is 1719 using ABC_D_E
11
4. Hints
4.1 Explaining the following example of the third kind of input
(Please convert *** minimally):
$ python3 roman_arabic.py
How can I help you? Please convert ABCADDEFGF minimally
Sure! It is 49269 using BA_C_DEF_G
First, remember the two important Roman numeral rules below:
1. A Roman symbol is repeated three times but not more than that. However, the symbols V (5),
L (50) and D (500) are never repeated.
2. The Roman symbols V (5), L (50) and D (500) are never written to the left of a symbol of
greater value, i.e., V (5), L (50) and D (500) are never subtracted. The symbol I (1) can be
subtracted from V (5) and X (10) only. The symbol X can be subtracted from L (50) and C (100)
only.
Note also that "minimally" means we are looking for a generalised Roman symbols that can
convert the given numeral into a smallest integer number.
Let us start assigning Roman numeral values from the right-hand side such that the value is
minimum.
Starting with F, we can see it is repeated and we have to assign the minimum value to FGF in
order to assign the minimum value to F. From a number of various combinations, we know
that the only possible solution here is F=10 and G=1 (try out combinations of 1, 5, 10 here to
see why this is the right one). Thus FGF=19.
Let us move now to the next element, which is E. We also need to consider the element after
E in order to assign a smaller combination, if possible, in this case. The next element is D,
which is repeated and therefore cannot be less than E. Thus, we assign E the smallest number
not used yet, which is 50. Moving on to D, since it is repeated, it cannot be greater than the
next element A. Thus, we assign the smallest number not yet used which is 100 to D.
Till now, our number DDEFGF is resulting in 269 using DEF_G (value 5 not assigned).
The next element is A and it is repeated. To assign a value to A, we must assign a value so that
ABCA does not violate Roman numeral rules. That is, A < B and B > C. Because of AB (A and B
being next to each other), we cannot assign A as 500 (500 cannot be subtracted from any
number).
12
Let us say we assign 1000 to A. Then B can be either 5000 or 10000. B cannot be 5000 because
that would mean C can only be 500. Also, B cannot be 10000 as it would mean C should be
5000 or 500 (both are invalid assignments).
Let us try to assign 10000 to A (it cannot be assigned 5000 since it is repeated). B can be either
50000 or 100000. If B is 50000, C can be either 5000, 1000 or 500. C cannot be 5000 or 500
(since they be subtracted from any number). C can be 1000.
Consequently, the smallest we can come up with here is 10000 for A, 50000 for B, and 1000
for C, and ABCA = 50000 - 10000 + 10000 - 1000 = 49000.
Thus, the total becomes 49269 using BA_C_DEF_G (values 5, 500 and 5000 not assigned).
4.2 More examples about the third kind of input
(Please convert *** minimally):
$ python3 roman_arabic.py
How can I help you? Please convert AZERTY minimally
Sure! It is 444 using ZAREYT
$ python3 roman_arabic.py
How can I help you? Please convert XXXVVVIII minimally
Sure! It is 333 using X_V_I
$ python3 roman_arabic.py
How can I help you? Please convert AhZhJ minimally
Sure! It is 691 using Ah_Z_J
$ python3 roman_arabic.py
How can I help you? Please convert BCBC minimally

請加QQ:99515681  郵箱:99515681@qq.com   WX:codehelp




 

標簽:

掃一掃在手機打開當前頁
  • 上一篇:代做CMPSC 443、代寫Project 2: Buffer Overflows
  • 下一篇:INFO-5060代做、代寫C++程序語言
  • 無相關信息
    昆明生活資訊

    昆明圖文信息
    蝴蝶泉(4A)-大理旅游
    蝴蝶泉(4A)-大理旅游
    油炸竹蟲
    油炸竹蟲
    酸筍煮魚(雞)
    酸筍煮魚(雞)
    竹筒飯
    竹筒飯
    香茅草烤魚
    香茅草烤魚
    檸檬烤魚
    檸檬烤魚
    昆明西山國家級風景名勝區
    昆明西山國家級風景名勝區
    昆明旅游索道攻略
    昆明旅游索道攻略
  • 短信驗證碼平臺 理財 WPS下載

    關于我們 | 打賞支持 | 廣告服務 | 聯系我們 | 網站地圖 | 免責聲明 | 幫助中心 | 友情鏈接 |

    Copyright © 2025 kmw.cc Inc. All Rights Reserved. 昆明網 版權所有
    ICP備06013414號-3 公安備 42010502001045

    久久久久久精品无码人妻_青春草无码精品视频在线观_无码精品国产VA在线观看_国产色无码专区在线观看

    99re6在线观看| 国产欧美精品一二三| 国产天堂在线播放| 欧美中文字幕在线观看视频| 欧美国产日韩另类 | 美女网站色免费| 青青视频在线播放| 欧美一级欧美一级| 欧美中日韩在线| 欧美视频在线第一页| 视频一区二区视频| 污污视频在线免费| 在线观看免费av网址| 美女网站免费观看视频| 精品免费国产一区二区| 欧美三级一级片| 日韩精品一区二区三区久久| 亚洲熟妇av日韩熟妇在线| 精品无码国模私拍视频| 妞干网在线观看视频| 蜜臀av色欲a片无码精品一区| bt天堂新版中文在线地址| 男人c女人视频| 青青青青在线视频| 丰满少妇久久久| 欧美爱爱视频免费看| 欧美 日韩 国产 高清| 中国丰满人妻videoshd | 狠狠热免费视频| 韩国视频一区二区三区| 中文字幕永久视频| 爱爱爱爱免费视频| www.久久久久久久久久久| 一级做a爱视频| 视频一区二区视频| 91网站在线观看免费| 日韩精品在线中文字幕| 国产精品333| 美女网站免费观看视频| 五月婷婷六月丁香激情| 在线免费看v片| 精品视频在线观看一区二区| 久激情内射婷内射蜜桃| 日本熟妇人妻xxxxx| 九色porny自拍| 懂色av粉嫩av蜜臀av| 中文字幕人妻熟女人妻洋洋| av之家在线观看| 亚洲国产精品三区| 2021狠狠干| 奇米精品一区二区三区| 四季av一区二区| 国产盗摄视频在线观看| 国产免费黄视频| mm131国产精品| 免费视频爱爱太爽了| 男人天堂成人在线| 免费观看黄色的网站| 成品人视频ww入口| www.com黄色片| 国产精品久久久久久久久电影网| aaaaaa亚洲| 五月天男人天堂| 欧美v在线观看| 99中文字幕在线| 五十路熟女丰满大屁股| 免费看a级黄色片| www.99riav| 免费激情视频在线观看| 熟女熟妇伦久久影院毛片一区二区| 免费看国产曰批40分钟| 17c国产在线| 国产91美女视频| 女女同性女同一区二区三区按摩| 无罩大乳的熟妇正在播放| 久久国产精品网| 一本色道无码道dvd在线观看| 成人精品视频一区二区| 一级做a免费视频| 欧美精品久久久久久久久久久| 久久久久久久久久福利| 免费看污污视频| 在线视频日韩一区| 久草视频国产在线| 亚洲综合婷婷久久| 日韩a∨精品日韩在线观看| 国产乱女淫av麻豆国产| 亚洲 高清 成人 动漫| 中国一级大黄大黄大色毛片| 亚洲综合在线网站| 精品一区二区三区无码视频| 图片区乱熟图片区亚洲| 人妻丰满熟妇av无码区app| 97中文字幕在线| 亚洲色图偷拍视频| 日本一本二本在线观看| 一二三四中文字幕| 中文字幕国产免费| wwwxxx黄色片| 给我免费播放片在线观看| 一区二区三区国产好的精华液| 欧美亚洲日本在线观看| 欧美综合在线播放| 免费看日本黄色| 日本女人高潮视频| 亚洲成人手机在线观看| 天堂在线资源视频| 激情六月丁香婷婷| 欧美大片在线播放| 日韩av高清在线看片| 色哟哟免费网站| 1314成人网| 深爱五月综合网| 特黄视频免费观看| 国产精品视频分类| 最新中文字幕2018| 日本爱爱免费视频| 激情综合网俺也去| 午夜免费精品视频| 欧美亚洲日本在线观看| 无码人妻丰满熟妇区五十路百度| 少妇高潮毛片色欲ava片| 欧美中文字幕在线观看视频| 日韩精品免费一区| 欧美一二三不卡| 欧美黄网在线观看| 日韩精品一区二区三区四| 成年丰满熟妇午夜免费视频| 欧洲美女和动交zoz0z| 91麻豆天美传媒在线| 男人添女人下部视频免费| 欧洲精品一区二区三区久久| 91视频 -- 69xx| 成人观看免费完整观看| 波多野结衣天堂| 粉色视频免费看| 中文字幕一区二区三区四区五区人| 欧美一级黄色录像片| 91动漫在线看| 黑森林福利视频导航| 欧美成人黄色网址| 97人人模人人爽人人澡| 玖玖精品在线视频| 台湾无码一区二区| 18禁免费无码无遮挡不卡网站| 黑森林福利视频导航| 粉色视频免费看| 青青在线免费视频| 人妻av中文系列| 999精品视频在线| 欧美xxxxxbbbbb| 欧美精品在欧美一区二区| 5月婷婷6月丁香| 亚洲成人天堂网| 国产高清不卡无码视频| 欧美 国产 综合| 狠狠干狠狠操视频| 国产精品视频一二三四区| 妺妺窝人体色www在线小说| av污在线观看| 久久av高潮av| 国产福利一区视频| 手机看片日韩国产| 免费欧美一级视频| 久久久久久久久久一区| 久久这里只有精品8| 116极品美女午夜一级| 国产精品自在自线| 男女视频网站在线观看| 一区二区三区视频网| 国产激情在线看| 99视频在线免费| 无码人妻精品一区二区蜜桃百度| 777久久久精品一区二区三区| 国产三级三级看三级| www.亚洲视频.com| 一本久道中文无码字幕av| 99视频精品全部免费看| www黄色在线| 无码人妻精品一区二区蜜桃网站| 黄色成人免费看| 国产二区视频在线| 国产精品自在自线| 欧美三级午夜理伦三级| 国产激情在线看| 色播五月激情五月| 人妻有码中文字幕| 欧美 亚洲 视频| 91女神在线观看| 日本一区二区黄色| 日韩最新中文字幕| 成年人在线观看视频免费| 黄色激情在线视频| 国产精品中文久久久久久| 99免费视频观看| 免费看国产一级片| 伊人网在线免费| 婷婷中文字幕在线观看| 91最新在线观看| 国产日韩一区二区在线观看|